Advent of Code Day 7 this year is another problem that's more about the math than about the programming, so we won't see much in the way of new functional techniques. Still, there's some interesting bits in there.

Today we need to calculate the fuel costs of moving a bunch of crabs in submarines all into a line. (Don't ask. Really, don't ask.) Essentially we want to center-align a series of points using the least "cost" possible. Crab positions are represented by a single number, as crabs can only move horizontally. (Because crabs.)

The trick for today is realizing that the crabs don't matter; it's a distance-cost calculation. In part 1, the cost for a crab to move one space toward whatever alignment number we want to pick is 1.

*Continue reading this post on PeakD.*